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Damm [24]
3 years ago
8

N a classroom of 33 students, the ratio of boys to girls is 3 : 8. How many boys are in the class?

Mathematics
1 answer:
tiny-mole [99]3 years ago
4 0

3 boys + 8 girls = 11 students

3 boys/ 11 students = x boys /33 students

using cross products

3 * 33 = x*11

divide by 11

99/11 = x

x=9

There are 9 boys

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What value for x will make the equation true?
Rama09 [41]

Answer:

C . 4

Step-by-step explanation:

step 1 : -3 multiply with inside of the ( 7x-5 )

= -21x + 15

step 2 : then it will be 21x + 15 = 87 + 3x

step 3 : switch between the odds into like this

21x - 3x = 87 - 15

step 4 : subtract it all

18x = 72

step 5 : bring 18 to the other side

x = 72/18

step 6 : to find the ans of x is just calculate them

x = 72 ÷ 18

= 4

Or you can do like these ⬇️

-3 ( 7x - 15 ) = 87 + 3x

21x + 15 = 87 + 3x

21x - 3x = 87 - 15

18x = 72

x = 72/18 or 72÷18

x = 4

4 0
2 years ago
3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0
Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

6 0
3 years ago
Read 2 more answers
A watering can contained 512 quarts water. After all the plants were watered, only 4 cups remained. How many cups of water were
irga5000 [103]

Answer:

18 cups.

Step-by-step explanation:

7 0
3 years ago
Alina and Asim share Rs 210 in the ratio 2:5. How much money did each of them get?
slavikrds [6]

Answer:

Step-by-step explanation:

Alina=2x---eq(1)

Asim=5x----eq---(2)

So,we get

2x+5x=210

7x=210

x=30

Now,Putting '30' in eq 1 and eq 2

2*30=60

5*30=150

Therefore Alina got 60 Rs while Asim got 150 Rs

5 0
3 years ago
Find the sum of the first 18 terms of the arithmetic sequence whose nth term is an = 3n - 1.
vodka [1.7K]

Answer:

495

Step-by-step explanation:

In order to find the sum of the first 18 terms you have to find the 18th term and the first term using the equation given.

a1=3(1)-1        a1=2

a18=3(18)-1   a18= 53

Then plug in 53 for an, 18 for n, and 2 in for a1 in the sum equation: Sn=n/2(a1+an)  

Sn=18/2(2+53)  Solve for sn= 495

7 0
3 years ago
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