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IRISSAK [1]
3 years ago
7

15^1/5 rewrite in radical form

Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

\sqrt[5]{15}

Step-by-step explanation:

<u>A number to 1/5 is the </u>\sqrt[5]{n}<u />

<u>A number to 1/3 is the </u>\sqrt[3]{n}<u />

So, since the number is 15 to the 1/5, it is \sqrt[5]{15}

Answer:  \sqrt[5]{15}

Tresset [83]3 years ago
7 0

Answer:

15^{\frac{1}{5} } = \sqrt[5]{15}

Step-by-step explanation:

recall that

a^{\frac{1}{b} }  = \sqrt[b]{a}

if we apply this to our case,

15^{\frac{1}{5} } = \sqrt[5]{15}

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Answer:

B.0.25

Step-by-step explanation:

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2 dollars gained in July 2 dollars gained in August and 5 dollars lost in September is -1

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3 years ago
Al saves pennines. He agreed to give 6/13 of his pennines to Bev if she would give 6/13 of what she got from Al to Carl and if C
Anuta_ua [19.1K]

Answer:

24,167 pennies

Step-by-step explanation:

Let's see what happens if we say Al had 1000 pennies.

Bev would get 6/13 of 1000 which is  462 pennies. ((6/13)*1000)

Continuing like this Carl would get (6/13)*462 = 213

Dani would get 213(6/13)=98

Now, another way of writing this is 1000*(6/13)*(6/13)*(6/13).  hopefully that makes sense, if not let me know.

Anyway, what is another way of writing this?  If it isn't clear how else can you write 3*3*3*3?  Exponents is the answer.  3*3*3*3=3^4 and (6/13)*(6/13)*(6/13)= (6/13)^3, so you can write the whole equation as 1000(6/13)^3=98

Now, using the information given in the question we know how much is gotten by Dani as well as (6/13)^3, but we don't know how much we start with.  So instead of 1,000 like I showed lets use a variable x.

x*(6/13)^3 = 2376

Now you can use algebra to solve for x

x*(6/13)^3 = 2376 step one let's just figure out what (6/13)^3 is.

x*(216/2197) = 2376  Now here you can either divide by 216/2197 or multiply by 2197 then divide by 216, it's the same thing.

x = 24167

You can double check too with 24167*(6/13)^3

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3 years ago
Due soon please help
Radda [10]

Answer:

c=38 degrees

Step-by-step explanation:

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