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gtnhenbr [62]
3 years ago
9

Complete the equation of the line through (6,-6) and (8,8)

Mathematics
1 answer:
noname [10]3 years ago
6 0

Answer:

y = 7x - 48

Step-by-step explanation:

To find the equation of the line

y = mx + c

Step 1 : find the slope

( 6, -6) ( 8, 8)

x_1 = 6

y_1 = -6

x_2 = 8

y_2 = 8

Insert the values into

m =( y_2 - y_1) /( x_2 - x_1)

m - slope

m = (8 - (-6)) / (8 -6 )

m = 8 +6 / 8 - 6

m = 14 / 2

m = 7

Step 2: substitute slope into intercept form equation

y = mx + c

y = 7x + c

Step 3: substitute either point into the equation in step 2

y = 7x + c

Let's pick point ( 8,8)

y = 8

x = 8

y = 7x + c

8 = 7(8) + c

8 = 56 + c

8 - 56 = c

c = 8 - 56

c = -48

Substitute the value of c back into the equation

y = 7x + c

y = 7x - 48

The equation of the line is

y = 7x - 48

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Please help this for my pre calculus finals
dsp73

Answer:

a) It will take 17.71 years

b) It will take 17.58 years

c) I will earn $6.60 more in compound continuously

Step-by-step explanation:

a) Lets talk about the compound interest

- The formula for compound interest is A = P (1 + r/n)^(nt)

, Where:

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial deposit)

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound quarterly

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ n = 4

∴ t = ?

∵ A = P (1 + r/n)^(nt)

∴ 6000 = 2000 (1 + 0.0625/4)^4t ⇒ divide both sides by 2000

∴ 3 = (1.015625)^4t ⇒ insert ㏑ for both sides

∴ ㏑(3) = ㏑(1.015625)^4t

∵ ㏑(a)^b = b ㏑(a)

∴ ㏑(3) = 4t ㏑(1.015625) ⇒ divide both sides by ㏑(1.015625)

∴ 4t = ㏑(3)/㏑(1.015625) ⇒ divide both sides by 4

∴ t = [㏑(3)/㏑(1.015625)] ÷ 4 = 17.71

* It will take 17.71 years

b) Lets talk about the compound continuous interest  

- Compound continuous interest can be calculated using the formula:

  A = P e^rt  

- A = the future value of the investment, including interest

- P = the principal investment amount (the initial amount)

- r = the interest rate  

- t = the time the money is invested

* Lets solve the problem

∵ The money deposit is $2000

∵ The rate is 6.25%

∵ The interest is compound continuously

∵ The future value is $6000

∴ P = 2000

∴ A = 6000

∴ r = 6.25/100 = 0.0625

∴ t = ?

∵ A = P e^rt  

∴ 6000 = 2000 e^(0.0625 t) ⇒ divide both sides by 2000

∴ 3 = e^(0.0625 t) ⇒ insert ㏑ to both sides

∴ ㏑(3) = ㏑[e^0.0625 t]

∵ ㏑(e^a) = a ㏑(e) ⇒ ㏑(e) = 1 , then ㏑(e^a) = a

∴ ㏑(3) = 0.0625 t ⇒ divide both sides by 0.0625

∴ t = ㏑(3)/0.0625 = 17.5778

* It will take 17.58 years

c) If t = 5 years

# The compound quarterly:

∵ A = P (1 + r/n)^(nt)

∴ A = 2000 (1 + 0.0625/4)^(4×5)

∴ A = 2000 (1.015625)^20 = $2727.08

# Compound continuously

∵ A = P e^(rt)

∴ A = 2000 e^(0.0625×5) = $2733.68

∴ I will earn = 2733.68 - 2727.08 = $6.60

* I will earn $6.60 more in compound continuously

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Ill give brainlist
Mariana [72]

The missing step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that; 76 - 1.85

<h3>How to Solve Mathematical Order of Operations?</h3>

We want to know the steps to solving the expression the quantity of the sum of six squared plus two divided by the absolute value of negative 0.5 − 14.8 ÷ 8

This can be expressed as;

6² + 2 ÷ |-0.5| - 14.8 ÷ 8

Thus, the next step which is step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that;

76 - 1.85

Read more about Order of Operations at; brainly.com/question/27529825

#SPJ1

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Which of the following is not a congruence transformation?
VladimirAG [237]

\bold{Heya!}

Your answer to this is :

<h2>C. Stretching.</h2>

<h2>→ <u>Explanation:-</u></h2>

<u />

Because the other one is congruent together.

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

5 0
2 years ago
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