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2 years ago

Complete the equation of the line through (6,-6) and (8,8)

Mathematics

1 answer:

noname [10]2 years ago

6 0

Answer:

y = 7x - 48

Step-by-step explanation:

To find the equation of the line

y = mx + c

Step 1 : find the slope

( 6, -6) ( 8, 8)

x_1 = 6

y_1 = -6

x_2 = 8

y_2 = 8

Insert the values into

m =( y_2 - y_1) /( x_2 - x_1)

m - slope

m = (8 - (-6)) / (8 -6 )

m = 8 +6 / 8 - 6

m = 14 / 2

m = 7

Step 2: substitute slope into intercept form equation

y = mx + c

y = 7x + c

Step 3: substitute either point into the equation in step 2

y = 7x + c

Let's pick point ( 8,8)

y = 8

x = 8

y = 7x + c

8 = 7(8) + c

8 = 56 + c

8 - 56 = c

c = 8 - 56

c = -48

Substitute the value of c back into the equation

y = 7x + c

y = 7x - 48

The equation of the line is

y = 7x - 48

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Pepsi [2]

Answer:

The error made is that the graph of $y=x^{2} +3$ is a vertical translation up by 3, instead of down.

Step-by-step explanation:

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3 0

2 years ago

Find the area of the shaded segment of the circle.

vredina [299]

Answer:

Around 5.5 square meters

Step-by-step explanation:

You can start by finding the area of the segment. Since the rest of the circle that is not in the segment is 240 degrees, the segment is 120 degrees or a third of the circle. You can therefore find the area of that segment with the formula $\frac{1}{3} \pi r^2 =3\pi$ square meters. Now, you need to find the area of the triangle inside the sector. This is more difficult than last time, because it is not a 90 degree angle. However, you can solve this by dividing this triangle into two 30-60-90 triangles, which you know how to find the ratio of sides for. In a 30-60-90 triangle, the hypotenuse is twice the length of the smallest leg, and the larger leg is $\sqrt{3}$ times larger than the smaller leg. In this case, these dimensions are a base of $\frac{3}{2}$ for the smaller leg and $\frac{3\sqrt{3}}{2}$ for the larger leg, or the base. Using the triangle area formula and multiplying by 2 (because remember, we divided the big triangle in half), you get $\frac{9\sqrt{3}}{4}$ square meters. Subtracting this from the area of the segment, you get about 5.5 square meters. Hope this helps!