14.42 is your distance formula
(1,0) is the midpoint
if you need the forma for distance it is x2-x1 squared + y2-y1 squared then square root it
Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then

Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
Subtract 19 from both sides
-3x=2+x
Subtract x from both sides
-4x=2
Divide both sides by -4
x=-1/2
Final answer: x=-1/2
Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

so.. that'd be the V(x) for such box, now, where is the maximum point at?

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.
so, the volume will then be at