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miss Akunina [59]
3 years ago
11

27 × 8 ÷ 2 = ??? Step by step

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

108

Step-by-step explanation:

multiply 27 x 8

27x8=216

divide 216/2

= 108

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Is (2,4) a solution of 2x - 7y < -10
Free_Kalibri [48]

Yes, (2,4) is the solution of 2x-7y<-10

HOPE THIS WILL HELP YOU

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Please help me with this ! ! ! ! !
melisa1 [442]

Answer:

First choice: m = -4

Step-by-step explanation:

The second equation is already solved for n, so lets's use the substitution method and substitute m - 2 for n in the first equation.

m - 2n = 8

m - 2(m - 2) = 8

m - 2m + 4 = 8

-m + 4 = 8

-m = 4

m = -4

8 0
3 years ago
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15 Points!!!!!!!!! Mike attends basketball practice sessions every week. The coach assesses his progress at the end of each sess
Naily [24]

Answer:

In the case of Mike's free throws, the Domain that describes this relationship can be either B or D.

Step-by-step explanation:

In the case of a relationship that represents a 'constant' increase or decrease, we know that there will be an independent and dependent variable.  The independent variable is our 'x' value and the dependent variable is our 'y' value.  In this case, they tell us that the number of free throws Mike misses is dependent on the number of practices sessions he has attended.  Therefor, 'x' would represent the number of practices and 'y' would represent the number of missed free throws. At the start, before practices or an 'x' value of 0, Mike, misses 6 free throws.  He continues to decrease his missed throws by for each practice, until the sixth practice where he misses none.  So, the 'x' values would be 0, 1, 2, 3, 4, 5, and 6.  This can be shown by letter 'B', which includes all numbers, or letter 'D', which represents all numbers between, and including 0 and 6.

6 0
3 years ago
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A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the
MrRissso [65]

Answer: The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

Step-by-step explanation:

Given : A kite is being flown at 45^{\circ} . The string of the kite is 120 feet long.  

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}

hence, The height of the kite above the point at which the string is held is 120\sqrt{2} feet.

5 0
3 years ago
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It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
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