<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
1.25*(t)+7=43.25
To solve the 2nd one, you must do 43.25 - 7 = 26.25
36.25 divided by 1.25 = 29
I can only assume that you meant, "Solve for x:"
Apply the exponent 3/2 to both sides of this equation. The result will be
3/2
343 = x/6.
Multiplying both sides by 6 isolates x:
3/2
6*343 = x Since 7^3 = 343, the expression for x
can be rewritten as
3/2
6*(7^3) = x which can be further simplified, as follows:
x = 6^(3/2)*7^(9/2), or:
x = 6^(3/2)*7^(8/2)*√7, or
x = 6^(3/2)*7^4*√7
Answer:
Step-by-step explanation:
Assuming the number of tickets sales from Mondays is normally distributed. the formula for normal distribution would be applied. It is expressed as
z = (x - u)/s
Where
x = ticket sales from monday
u = mean amount of ticket
s = standard deviation
From the information given,
u = 500 tickets
s = 50 tickets
We want to find the probability that the mean will be greater than 510. It is expressed as
P(x greater than 510) = 1 - P(x lesser than or equal to 510)
For x = 510
z = (510 - 500)/50 = 0.2
Looking at the normal distribution table, the probability corresponding to the z score is 0.9773
P(x greater than 510) = 1 - 0.9773 = 0.0227
Answer:6 i think
Step-by-step explanation:
