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3 years ago

A division problem is shown below.

Mathematics

1 answer:

masya89 [10]3 years ago

7 0

4 1/3 : 5 1/6
To divide fractions, you first must find the improper version of each (4 1/3 = 13/3; 5 1/6= 31/6)
Now you have 13/3 : 31/6.
Since to divide fractions, you find the reciprocal of the second number in the equation and multiply it by the first number(the reciprocal is when the numerator and denominator is switched)
Meaning that to solve this you need to multiply 13/3 * 6/31

Meaning that the answer is the first one

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3 years ago

A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea

weqwewe [10]

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a) 8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

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3 years ago

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2 Express answer as a common fraction. Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

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3 years ago