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Marina86 [1]
3 years ago
13

What is the bigger number, a googol or a billion?

Mathematics
2 answers:
DENIUS [597]3 years ago
6 0

googol is the word for the number of infinity or more than any known number. So a billion is smaller than googol


Doss [256]3 years ago
3 0
A googol is bigger than a billion.
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Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
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Answer:

(A) 0.006593 or 0.6593%

(B) 0.01538 or 1.538%

Step-by-step explanation:

The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

n=\frac{15!}{(15-3)!3!}=\frac{15*14*13}{3*2*1}\\n=455\ ways\\

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

P(N=1) = \frac{3}{455}=0.006593 =0.6593\%

(B) There are three possibilities  for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

P(N>0) =P(N=1)+P(N=2)+P(N=3) \\P(N>0) = \frac{3}{455}+ \frac{3}{455}+ \frac{1}{455}\\P(N>0) =0.01538 =1.538\%

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3 years ago
What is the slope of the line y = 8?<br> a.0<br> b.4<br> c.8<br> d.undefined
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The American Psychological Associated conducted a survey in 2003 of psychologists to estimate the average incomes for psychologi
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This question is incomplete, the complete question;

The American Psychological Associated conducted a survey in 2003 of psychologists to estimate the average incomes for psychologists based on their academic degree and years of experience. 36 psychologists responded who had a just received their masters degree in 2003. The average was $48,800 with a standard deviation of $16,800.

The 95% Confidence Interval is ($, $ )

Answer:

at 95%, confidence interval is ( $43312, $54288 )

Step-by-step explanation:

Given the data in the question;

sample size n = 36

mean x' = 48,800

standard deviation σ = 16,800

at 95% confidence level;

∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

z critical value, Z_{\alpha/2 = 1.96

now, confidence interval for population mean is given by the formula

x' ±  Z_{\alpha/2( σ/√n )

so we substitute

⇒ 48800 ±  1.96( 16800/√36 )

⇒ 48800 ±  1.96( 2800 )

⇒ 48800 ±  5488

⇒ 48800 -  5488, 48800 +  5488

⇒ ( 43312, 54288 )

Therefore, at 95%, confidence interval is ( $43312, $54288 )

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