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sergeinik [125]
3 years ago
5

Given: Tangents LA and LB m∠AOB=110° Find: m∠ALO.

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

m<ALO=35°

Step-by-step explanation:

we know that

The right triangle AOL is congruent with the right triangle BOL

because

OA=OB=radius of the circle

OL is a common side

LA=LB ---> by applying the Pythagoras theorem

therefore

m<AOL=m<AOB/2

m<AOL=110°/2

m<AOL=55°

Remember that

m<AOL+m<ALO=90° ------> by complementary angles

m<ALO=90°-55°=35°

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