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Butoxors [25]
3 years ago
13

Help me!! will give brainly helppppp

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

SJSGGSHB AAJAM SLE AS THE MONSY UWY WHY AH AI

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Ms. Groves has trays of paints for students in her art class each tray ahe 5 colours one of the colours is purple what fraction
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The answer is 4/20 are purple out of 20 trays reduced to 1/5
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The school is located where Wilson Street and Green Street intersect. Which ordered
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(5,3) is the answer for the current question

4 0
3 years ago
The area of the shaded portion of the rectangle is how many units larger than the area of the unshaded portion of the rectangle?
slega [8]

Answer:

(x^{2}-x-2)\ units^{2}

Step-by-step explanation:

step 1

Calculate the area of the shaded portion

A1=(2x+3)(x+1)\\ \\A1=2x^{2}+2x+3x+3\\ \\A1=(2x^{2}+5x+3)\ units^{2}

step 2

Calculate the area of the unshaded portion

A2=(x+5)(x+1)\\ \\A2=x^{2}+x+5x+5\\ \\A2=(x^{2}+6x+5)\ units^{2}

step 3

Find the difference of the areas

A1-A2=(2x^{2}+5x+3)-(x^{2}+6x+5)=(x^{2}-x-2)\ units^{2}

7 0
4 years ago
Please help picture shown and show workkkk
tankabanditka [31]
1)
Area of largest circle - 2 * Area of one smaller circle = Area of the shaded region

AE = diameter of large circle = 48cm
radius of larger circle = diameter / 2 = 48cm / 2 = 24cm

4 circles fit across the diameter of the circle, so the diameter of the larger circle = 4 * diameter of the smaller circle
diameter of larger circle = 48cm = 4 * diameter of the smaller circle
diameter of the smaller circle = 48cm / 4 = 12cm
radius of smaller circle = diameter / 2 = 12cm / 2 = 6cm

Area of a circle = pi * r^2

Now plug the circle area equation into the first equation:
A_{shaded}=A_{l} - 2*A_{s}\\\\A_{shaded}=[\pi (r_{l})^{2}]-2*[\pi (r_{s})^{2}]\\\\A_{shaded}=[\pi (48cm)^{2}]-2*[\pi (6cm)^{2}]\\\\A_{shaded}=2304\pi-72\pi\\\\Area\ of\ shaded\ region\ is\ 2232\pi.


2)
Area of the shaded region = 2/7 * Area of the smaller circle
Area of the unshaded region = Area of larger circle + Area of smaller circle - Area of shaded region * 2
A_{unshaded}=[\pi (r_{1})^{2}]+[\pi (r_{2})^{2}]-2*[\pi (r_{2})^{2}]*\frac{2}{7}\\\\A_{unshaded}=[\pi (10cm)^{2}]+[\pi (7cm)^{2}] -\frac{4}{7}[\pi (7cm)^{2}]\\\\A_{unshaded}=100\pi\ cm^{2}+49\pi\ cm^{2}-\frac{4*49\pi\ cm^{2}}{7}\\\\A_{unshaded}=149\pi\ cm^{2}-(4*7*\pi\ cm^{2})\\\\A_{unshaded}=149\pi\ cm^{2}-28\pi\ cm^{2}\\\\\\A_{unshaded}=121\pi\ cm^{2}
3 0
4 years ago
What is the better deal? Deal#1. Is a 20% discount followed by a second discount of 15%. Deal#2. Is one 35% discount
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Deal 1 is the better deal because if it was $100, then 1 would be $60 and 2 would be $65.
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3 years ago
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