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Sidana [21]
4 years ago
8

I'm not sure how to answer this question. Could someone please help explain it?

Mathematics
1 answer:
qaws [65]4 years ago
3 0
Consider the parent function, \displaystyle{ f(x)= \sqrt{x}. 

The function f, takes a number x, and produces the square root of it, for example we have the points:

(1, 1), (4, 2), (25, 5), (100, 10).


The function \displaystyle{ g(x)= \sqrt{x-5}, takes a value x, subtracts it 5, and then produces the square root of this difference.


So to produce the values 1, 2, 5, 10 given in the previous function, we need to 

plug in the function not 1, 4, 25, and 100, but 6, 9, 30, 105.


Comparing  : (1, 1), (4, 2), (25, 5), (100, 10) of (x, f(x)) with 

                      (6, 1), (9, 2), (30, 5), (105, 10) of (x, g(x)),

we see that the graph of g is the same as the graph of f shifted 5 units right.



In general, the graph of  y=f(x-a), where a is a positive number, is the graph of y=f(x) shifted a units right.  

Answer: C
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3/10y - 2/5 i need to find the coefficient and i dont know how
Rudik [331]

\frac{3}{10y} -  \frac{2}{5} =  \frac{3 - 4y}{10y}

7 0
3 years ago
Endpoint: (1,7), midpoint: (-10,10)
algol [13]

The answer is (-21, 13) for The second endpoint.  

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 1)/2 = -10

Kx + 1 = -20

Kx = -21

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + 7)/2 = 10

Ky + 7 = 20

Ky = 13

This gives us the final point of (-21, 13)

5 0
3 years ago
Hi. I need help with these questions.<br> See image for question.<br> Answer 14 and 13
irinina [24]

Answer:

  • 13) 36x² + 9x - 4 = 0
  • 14) 21x² + 20x + 100 = 0

Step-by-step explanation:

13.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 4x² - 3x - 4 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of 1/(3α) and 1/(3β)
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -(-3)/4 = 3/4
  • αβ = c/a ⇒ αβ = -4/4 = - 1

<u>New equation is:</u>

  • (x - 1/(3α))(x - 1/(3β)) = 0
  • x² - (1/(3α) + 1/(3αβ))x + 1/(3α3β) = 0
  • x² - ((3α + 3 β)/(3α3β))x + 1/(3α3β) = 0
  • x² - ((α + β)/(3αβ))x + 1/(9αβ) = 0
  • x² - (3/4)/(3(-1))x + 1/(9(-1)) = 0
  • x² + 1/4x - 1/9 = 0
  • 36x² + 9x - 4 = 0

===================

14.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 3x² +2x + 7 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of α + 1/β and β + 1/α
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -2/3
  • αβ = c/a ⇒ αβ = 7/3

<u>New equation is:</u>

  • (x - (α + 1/β))(x - (β + 1/α)) = 0
  • x² - (α + 1/β + β + 1/α)x + (α + 1/β) (β + 1/α) = 0
  • x² - (α + β + (α + β)/αβ )x + αβ + 1/αβ + 2 = 0
  • x² - (-2/3 - (2/3)/(7/3))x + 7/3 + 1/(7/3) + 2 = 0
  • x² - (-2/3 - 2/7)x + 7/3 + 3/7 + 2 = 0
  • x² + (14 + 6)/21x + (49 + 9 + 42/21) = 0
  • x² + 20/21x + 100/21 = 0
  • 21x² + 20x + 100 = 0
8 0
3 years ago
How to calculate the perpendicular distance from a line produced?? Thanks!!!
kykrilka [37]

Answer:d=a2+b2 ∣a(x0)+b(y0)+c∣. So given a line of the form a x + b y + c ax+by+c ax+by+c and a point ( x 0 , y 0 ) , (x_{0},y_{0}), (x0,y0), the perpendicular distance can be found by the above formula.

Step-by-step explanation:

if that is any help

4 0
3 years ago
HELP!!! PLEASE!!! NOW!!!!!! ASAP!!!!
77julia77 [94]

Answer:

y < -5

Step-by-step explanation:

19 > -6 - 5y

add 6 to both sides

25 > - 5y

divide by -5

-5 > y

8 0
3 years ago
Read 2 more answers
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