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konstantin123 [22]
4 years ago
10

James has 6 stamps in his stamp collection. Roy has 12 stamps in his stamp collection. James adds 2 stamps to his stamp collecti

on. After James adds these stamps, what is the ratio of the number of stamps in James's collection to the number of stamps in Roy’s collection?
Mathematics
1 answer:
Phoenix [80]4 years ago
3 0
For every one stamp James has Roy has twice as much. So the ratio would be 1/2
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What do u add to 5 4/7 to get 7
enot [183]

Answer:

10/7

Step-by-step explanation:

5 4/7=39/7

x+39/7=7

x=7-39/7

x=49/7-39/7

x=10/7

6 0
4 years ago
Read 2 more answers
Graph the exponential function g(x)= 3/5^x
givi [52]
Hello!

You put the numbers in for x

3/5^-2 = 2.777
3/5^-1 = 1.667
3/5^0 = 1
3/5^1 = 0.6
3/5^2 = 0.36

The points are (-2, 2.777), (-1, 1.667), (0, 1), (1, 0.6), (2, 0.36)

Hope this helps!
3 0
4 years ago
Read 2 more answers
Initially a ship and a submarine are stationary at sea level, positioned 1.78km apart. The submarine then manoeuvres to position
poizon [28]
I’m assuming ‘dives further’ means to go directly down

the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.

let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)

then this become a simple trig problem:

A)

Let O be the position of of the ship, and C be the original position of the submarine.

therefore, not considering direction

|OC| = 1.78km = 1780m

|CA| = 45m

these are the adjacent and opposite sides of a right angled triangle.

But tan($) = opp/adj = |CA|/|OC| = 45/1780

therefore $ = arctan(45/1780) which is roughly 1.45 degrees,

B)

similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m


tan(¥) = 107/1780

¥ = arctan(107/1780) which is roughly 3.44 degrees






4 0
3 years ago
Given f(x)=x^2+5 and g(x)=2x^3-1 find (f/g)(-3)
AlekseyPX

For this case we have the following functions:

f (x) = x ^ 2 + 5\\g (x) = 2x ^ 3-1

By definition of composition of functions we have:

(f / g) (x) = \frac {f (x)} {g (x)}

Then substituting:

f (-3) = (- 3) ^ 2 + 5 = 9 + 5 = 14\\g (-3) = 2 (-3) ^ 3-1 = 2 (-27) -1 = -54-1 = -55

So:

(f / g) (- 3) = \frac {14} {- 55} = - 0.25

Answer:

(f / g) (- 3) = \frac {14} {- 55} = - 0.25

7 0
3 years ago
Help urgent plz!❤️❤️❤️Please please urgently
sleet_krkn [62]

Answer:

Problem 2): \left \{x\, |\,0\leq x\leq 240\,\,\right \}

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\left \{x\, |\,0\leq x\leq 240\,\right \}

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

6 0
3 years ago
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