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aleksandrvk [35]
2 years ago
6

Find three consicutive numbers that have the sum 96

Mathematics
1 answer:
In-s [12.5K]2 years ago
7 0

Answer:

31, 32, 33

Step-by-step explanation:

three consicutive numbers means 3 numbers in a row

sum 96 is the total you want to reach

31 + 32 + 33

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How to do the substitution in math?
seraphim [82]

Substitution method can be applied in four steps

Step 1:

Solve one of the equations for either <span>x = </span>or y = .

Step 2:

Substitute the solution from step 1 into the other equation.

Step 3:

Solve this new equation.

Step 4:

Solve for the second variable.


hope this helps you!

4 0
3 years ago
The questions is on the picture
allochka39001 [22]

Answer:

EASY:

Step-by-step explanation:

-7 > -12    

2 > -2

-5 < -3

|-9| is maybe 9.

|13| is 13.

|-5| is maybe 5.

5 0
3 years ago
Read 2 more answers
A pencil is `120` millimeters long.
leva [86]

Given the length of the pencil, the length of the marker is 130.8 millimeters.

<h3>What are percentages?</h3>

Percentage can be described as a fraction of an amount expressed as a number out of hundred. Percentages are represented %.

<h3>How long is the marker?</h3>

Length of the marker = (1 + percentage) x length of the pencil

(1.09) x 120 = 130.8 millimeters

To learn more about percentages, please check: brainly.com/question/25764815

6 0
2 years ago
The sandwiches at the bakery come in four sizes:
kaheart [24]
13 kids sandwiches X 4 inches = 52 inches  
22 small sandwiches X 6 inches = 132 inches
17 medium sandwiches X 8 inches = 136 inches
17 large sandwiches X 12 inches = 204 inches

52+132+136+204= 524 inches = 43.66 feet = 43.7 feet

7 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}
\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
3 years ago
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