Answer:

Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>
- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be

<h3>Case-2:</h3>
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,

<h3>Case-3:</h3>
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,

Thus our system of equations is

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

Now solve the equation accordingly:

Solving the equation for x and y yields:

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437
In order to get your answer add 8.1 + 4.9 = 13. Then to double check subtract 13 by 8.1 which equals 4.9. Hope this helps!
Hamburgers = h
fries = f
5h + f = $10.24
h + 5f = $5.84
6h + 6f = $ 16.08
3h + 3f = $8.04
The correct answer is C.
Answer:
The answer is 6 wholes and 7/8ths.
Answer:
2
Step-by-step explanation:
2021/7 leaves a remainder of 5 so add 2 and that's the answer