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3 years ago

What is 65, 124 rounded to the nearest thousand

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

65,000

Pretty sure bc 1 isn't big enough to move the 5 up a number

Bad White [126]3 years ago

5 0

Answer: 65,000

65,124
^
this number is the thousandths place

65,124
^
this number will determine the 5
^
if this number is 0,1,2,3, or 4 - the thousandths place stays the same, But if this number is 5,6,7,8, or 9 - you round the thousandths place up by one.

Spongebob youth

2 years ago

And that is why 65,000 is the answer

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Valentino's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is wha

trapecia [35]

Answer: Number of pizzas out of 4000 that is expected to be pan size

= 4000 * 168 / (326 + 309 + 247 + 168)

= 640

3 0

2 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

2 years ago

PLEASE HELP!!! i’ll give brainliest

tekilochka [14]

Answer:

x = $\sqrt{164$

Step-by-step explanation:

In order to find the hypothenuse, you need to do $8^{2} + 10^{2}$ . Which equals 164. Therefore, since $a^{2} +b^{2} =c^{2}$ , a=8, b=10, and c= $\sqrt{164$ .