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slava [35]
3 years ago
12

What is 65, 124 rounded to the nearest thousand

Mathematics
2 answers:
shtirl [24]3 years ago
7 0
65,000

Pretty sure bc 1 isn't big enough to move the 5 up a number
Bad White [126]3 years ago
5 0
Answer: 65,000 

65,124
  ^
this number is the thousandths place

65,124
      ^
this number will determine the 5
^ 
if this number is 0,1,2,3, or 4 - the thousandths place stays the same, But if this number is 5,6,7,8, or 9 - you round the thousandths place up by one. 
Spongebob youth
2 years ago
And that is why 65,000 is the answer
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Range of scores making up the interquartile ranger
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P(<em>Z</em> ≥ 1.53) ≈ 0.9375

You can transform any normally distributed variable <em>Y</em> to <em>Z</em> using the relation

<em>Z</em> = (<em>Y</em> - <em>µ</em>) / <em>σ</em>

where <em>µ</em> and <em>σ</em> are the mean and standard deviation of <em>Y</em>, respectively.

So if <em>s</em> is the standard deviation of <em>X</em>, then

(250 - 234) / <em>s</em> ≈ 1.53

Solve for <em>s</em> :

16/<em>s</em> ≈ 1.53

<em>s</em> ≈ 10.43

4 0
3 years ago
Please someone help me out
hichkok12 [17]

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3 0
3 years ago
What is the common denominator for 1/2 and 1/8
Snowcat [4.5K]

Answer:


Step-by-step explanation:

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7 0
3 years ago
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What is 6.12 as a fraction
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6 0
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A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.
Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

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