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guajiro [1.7K]
3 years ago
11

Rent-An-SUV charges an $80 fee to rent a truck and $12 per mile. Another rental company charges a $150 fee to rent a truck

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

The linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Since we are not told what to find, we can look for t<u>he linear equation that can be used to calculate daily car rentals</u>;

  • Let the charge amount be y
  • Let the amount per mile of the truck rent be x.

  • If rent-An-SUV charges an $80 fee to rent a truck and $12 per mile, this can be expressed in coordinate form as (12, 80)

  • Similarly, if another rental company charges a $150 fee to rent a truck and $8.50 per mile, this can also be written in a coordinate form as (8.50, 150)

The standard linear expression is given as f(x) = mx + b

  • m is the rate of change
  • b is the y- intercept

Get the rate of change;

m=\frac{150-80}{8.5-12}\\m=\frac{70}{-3.5}\\m=  -20\\

Get the y-intercept;

80 =  -20(12) + b

80 = -240 + b

b = 320

Get the required linear equation;

f(x) = mx + b

f(x) = -20x + 320

Hence the linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Learn more on linear equation here: brainly.com/question/12788590

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sveticcg [70]

Answer:

Step-by-step explanation:

12=3x-2y

2y+12=3x

2y=3x-12

y=(3x-12)/2

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To be parallel to the line above our line must have the same slope or m. The above line has a slope of 3/2 or 1.5 so the parallel line will be

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So y is either 184 or 481. 
Now, lets check
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That rules out 184
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