Answer:
31ft
Step-by-step explanation:
6 ft + 2.5 ft + 12 ft + 2.5 ft + 8 ft = 31ft
I assumed the slash in the space between 2.5ft and 12ft was an error, so I ignored it in the solution to this problem.
Besides that, perimeter is found by adding all sides of the shape or figure together, and the sum of that is the perimeter.
The basic formula for perimeter is:
base + height + base + height.
I do not think you square perimeter as you do area (e.g. 31ft^2).
Answer:
1
Step-by-step explanation:
6x+10=2x+14
6x-2x=14-10
4x=4
x=1
Answer:
Tangent segment ? I think. I don't know for sure because of the way you wrote the question- I got a bit confused.
Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.