Answer:
yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh
Step-by-step explanation:yniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era csacasccacwoh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh ollehyniar hcum oot sti ereh pleh esaelp retaw eht rednu ma i uoy era woh olleh
Answer:
the answerrrr is cccccc
Step-by-step explanation:
fvfvfvrfv
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%
Two parallel lines never intersect, therefore they will never have a solution.
One line could be x=6 and the other could be x=2
Hope this helps :)
