![\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{Days}{d}&\stackrel{Price}{P}\\ \cline{1-2} 1&\$115\\ 2&\$150&\leftarrow 115+\stackrel{35(1)}{35}\\ 3&\$185&\leftarrow 115+\stackrel{35(2)}{35+35}\\ 4&\$220&\leftarrow 115+\stackrel{35(3)}{35+35+35}\\ d&&\leftarrow 115+35d\\ \cline{1-2} \end{array}~\hfill \stackrel{part~A}{P(d)=35d+115} \\\\\\ ~\hspace{34em}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Ccc%7Cll%7D%20%5Ccline%7B1-2%7D%20%5Cstackrel%7BDays%7D%7Bd%7D%26%5Cstackrel%7BPrice%7D%7BP%7D%5C%5C%20%5Ccline%7B1-2%7D%201%26%5C%24115%5C%5C%202%26%5C%24150%26%5Cleftarrow%20115%2B%5Cstackrel%7B35%281%29%7D%7B35%7D%5C%5C%203%26%5C%24185%26%5Cleftarrow%20115%2B%5Cstackrel%7B35%282%29%7D%7B35%2B35%7D%5C%5C%204%26%5C%24220%26%5Cleftarrow%20115%2B%5Cstackrel%7B35%283%29%7D%7B35%2B35%2B35%7D%5C%5C%20d%26%26%5Cleftarrow%20115%2B35d%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D~%5Chfill%20%5Cstackrel%7Bpart~A%7D%7BP%28d%29%3D35d%2B115%7D%20%5C%5C%5C%5C%5C%5C%20~%5Chspace%7B34em%7D)
part B)
the slope is always in a linear equation, the coefficient of the independent variable, in this case namely "35".
35 or 35/1 dollars/day means
for every passing day the car is rented out, the charge is $35, so if you rent the car "d" days, you'll be charged 35d.
Your answer should be the 3rd choice. There is no solution.
4x^2-25= (2x)^2-5^2=(2x-5)(2x+5)
Used: a^2-b^2=(a+b)(a-b)
Answer:
Grade B score:
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73.3
Standard Deviation, σ = 9.7
We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
B: Scores below the top 5% and above the bottom 62%
We have to find the value of x such that the probability is 0.62
Calculation the value from standard normal z table, we have,
We have to find the value of x such that the probability is 0.05
![P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95](https://tex.z-dn.net/?f=P%28X%20%3C%200.95%29%20%3D%20%5C%5C%5C%5CP%28%20X%20%3C%20x%29%20%3D%20P%28%20z%20%3C%20%5Cdisplaystyle%5Cfrac%7Bx%20-%2073.3%7D%7B9.7%7D%29%3D0.95)
Calculation the value from standard normal z table, we have,
Thus, the numerical value of score to achieve grade B is
![76 \leq x \leq 89](https://tex.z-dn.net/?f=76%20%5Cleq%20x%20%5Cleq%2089)
Answer:
1/8
Step-by-step explanation:
1/4 = 2/8 so 3/8 - 2/8 = 1/8