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Katena32 [7]
3 years ago
10

Convert to slope intercept form. y + 6 = 4/5 (x + 3)

Mathematics
2 answers:
xenn [34]3 years ago
7 0
X = 5y + 30/4 - 3 is the answer.
zysi [14]3 years ago
6 0
All you need to do is subtract the 6 and distribute on the right side. 

y + 6 = 4/5x + 2 2/5
y = 4/5x - 3 3/5

Hope this helps!!

This random online calculator received the same answer: 

Second image is a picture of Desmos (online graphing calculator) with my answer plugged in: 

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Solve and simplify<br> 3. (y^2-7y-5)-(-3y^2+3y-4)
yKpoI14uk [10]

(y^2-7y-5)-(-3y^2+3y-4)=y^2-7y-5-(-3y^2)-3y-(-4)\\\\=y^2-7y-5+3y^2-3y+4

<em>combine like terms</em>

=(y^2+3y^2)+(-7y-3y)+(-5+4)=\boxed{4y^2-10y-1}

7 0
3 years ago
Help me please ...........
Llana [10]

Answer:

D.

\sqrt{384}

Step-by-step explanation:

\sqrt{384}

\sqrt{192 \times 2}

\sqrt{96 \times 2 \times 2}

2 \sqrt{48 \times 2}

2 \sqrt{24 \times 2 \times 2}

2 \times 2 \sqrt{12 \times 2}

4  \sqrt{6 \times 2 \times 2}

4 \times 2 \sqrt{6}

8 \sqrt{6}

Therefore Option D is correct..!

6 0
3 years ago
Aisha has 9 pizzas she is serving each person at a party 3/4 of a pizza.
Nikitich [7]

Answer:

12

Step-by-step explanation:

9/0.75=12.

7 0
3 years ago
Find the ratio created when AB is partitioned by C.
Blizzard [7]

Answer:

Step-by-step explanation:

From the picture attached,

Segment AB has been divided into four equal parts.

Let each part measures equal length = 1 unit

Point C is 2 units apart from both the points A and B.

Length of AC = Length of BC = 2 units

Therefore, point C will be the mid point of segment AB.

And ratio of AC and BC = 1:1

AC:BC = 1:1

Similarly, AC:AB = 2:4

                           = 1:2

And BC:AB = 2:4

                   = 1:2

8 0
2 years ago
Write the equation of a Line that is perpendicular to y=5/2x+3 and passes
koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

5 0
3 years ago
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