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Ganezh [65]
3 years ago
7

Line segment segment CD has a slope of negative start fraction two over three end fraction and contains point C(−3, −6). What is

the y-coordinate of point Q(−1, y) if segment QC is perpendicular to line segment segment CD question mark
y = 3
y = 0
y = −2
y = −3
Mathematics
1 answer:
Elanso [62]3 years ago
5 0
For perpendicular lines, the slopes are negative reciprocals of one another. Therefore, the slope of QC = 3/2

Using this into the formula of slope:
3/2 = (y + 6) / (-1 + 3)
y = -9

If the slope of CD is 2/3, then y works out to be -3.
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What happens to the value of the expression 5/x+5 as x decreases from a large positive number to a small positive number?
Tresset [83]

option 2. it increases

because as x decrease 5/x will increase which will overall increase the expression value

6 0
3 years ago
Consider a triangle ABC like the one below. Suppose that a=51, b=16, and A=108. (The figure is not drawn to scale.) Solve the tr
Blababa [14]

Answer:

B = 17.4°

C = 54.6°

c=43.7

5 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
What is the lateral area of the pyramid?
Mars2501 [29]
Lateral surface are = 2( 1/2 x 11 x 11.9) + 2( 1/2 x 9 x 12.3)

Lateral surface area = 130.9 + 110.7 = 241.6 ft²

Answer: 241.6 ft² (Answer C)
7 0
3 years ago
A line passes through the points (-1, -6) and (-4, 3). What is the equation of this line in slope-intercept form?
iVinArrow [24]

Answer:

A

Step-by-step explanation:

Slope = (3+6)/(-4+1)

          = 9/-3

          = -3

Y=mx+b

-6= -3×-1 +b

-6 = 3 +b

b = -9

6 0
3 years ago
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