Answer:
(x - 2)(3x^2 + 5)
Step-by-step explanation:
All four terms here have 3 as a factor. Factor out 3:
3x^(3)-6x^(2)+15x-30 => 3(x^3 - 2x^2 + 5x - 10)
The last two terms can be rewritten as 5(x - 2). The first two terms can be rewritten as 3x^2(x - 2). So (x - 2) is a factor of 3(x^3 - 2x^2 + 5x - 10). We get:
3x^2(x - 2) + 5(x - 2) = (x - 2)(3x^2 + 5)
The answer is 134 because 15 times 24 is 360 and 12 times 18 is 216 and 360-216 is 134
Answer:
Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Step-by-step explanation:
Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:
6000 + 3B + B = 24000
3B + B = 24000 - 6000
4B = 18000
B = 18000/4
B = 4500
S = 6000 + 3x4500
S = 6000 + 13500
S = 19500
Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.