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dolphi86 [110]
3 years ago
13

Solve the equation. −2 1/4=r−4/5 will give brainiest for the first correct answer!!!

Mathematics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

r = -1 9/20

Step-by-step explanation:

-2 1/4 = r - 4/5

Switch sides:

r - 4/5 = -2 1/4

Add 4/5 to both sides.

r = -2 1/4 + 4/5

Change the mixed numeral into a fraction:

r = -9/4 + 4/5

The LCD is 20.

r = -45/20 + 16/20

r = -29/20

r = -1 9/20

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An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
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Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Help! how would i work this out??
Alina [70]

Answer:

i can see it

Step-by-step explanation:

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