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3 years ago

Given f(x) = x2 - x3, find f(-10)

Mathematics

1 answer:

Nikitich [7]3 years ago

7 0

<h2>Value of f(-10) is 1100</h2>

Step-by-step explanation:

Given that f(x) = x² - x³

Here we need to find f(-10).

f(-10) = (-10)² - (-10)³

f(-10) = 100 - (-1000)

f(-10) = 100 + 1000

f(-10) = 1100

Value of f(-10) is 1100

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Lisa’s home is currently worth $150,000. When she purchased it five years ago, it was worth $180,000. Find the percent of change

Anestetic [448]

Answer:

16.7 percent decrease.

Step-by-step explanation:

Difference in value = 150,000 - 180,000

= -30,000

As a percent this = (-30,000 / 180,000) * 100

= -0.1667 * 100

= -16.67

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3 years ago

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All you have to do is start with one letter for example "T" and rotate the two after them until you run out of possibility like "TKE" "TEK" now if we were to rotate the letters after the first one again it would be "TKE" so we know that we are out of possibilities. Then you repeat with another letter.

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3 years ago

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What is the value of x in the equation 2.5(6x-4) = 10+4(1.5+0.5x)?

Phoenix [80]

Answer:

Step-by-step explanation:

As the equation is given in the question as follows.

2.5(6x-4)=10+4(1.5+0.5x)

open the bracket

2.5 × 6x - 2.5 × 4 = 10 + 4 × 1.5 + 4 ×0.5x

15x - 10 = 10 + 6 + 2x

15x - 2x = 16 + 10

13x = 26

x = 2

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2 years ago

At breakfast, restaurant charges $2 for the first cup of orange juice and then $1 for each refill which graph represents this si

liq [111]

Answer:

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Step-by-step explanation:

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y=x+1

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3 years ago

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Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

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2 years ago