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3 years ago

P-value for p = 0.23 is closest to: 0.006 or 0.40?

Mathematics

1 answer:

inn [45]3 years ago

4 0

Answer:

0.40 I'm pretty sure tbh

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the x-coordinate of the solution to the following system of equations?

tatyana61 [14]

Answer

X-2y = 2

3x + y = 6

Ox=-2

Ox=0

Ox=2

Ox=3

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Step-by-step explanation:

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3 years ago

Which is the rationalized form of the expression. A, B , C, or D?

grin007 [14]

Answer:

Step-by-step explanation:

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3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

4 years ago