Answer:

Step-by-step explanation:
Given the general equation of a circle represented as:
where:
(a, b) is the centre of the circle and r is the radius
Given the centre located a (1,3), to get the radius we will take the distance between the centre point of the circle the the point that lies on its circumference i.e (0,1).
Using the formula for calculating thee distance between 2 points, we have:

x1 = 1, y1 = 3, x2 = 0, y2 = 1

Substituting this values of the centre and radius of the circle into the general equation of a circle we have:

This gives the required equation of the circle.
Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)
We have the next equation of line:
y=1/2 x-2 (slope-intercept form y=mx+b)
the slope of this line is 1/2 (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2 (0,-2)
Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)
Answer: the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)
Answer:
is questions no 6 is the correct answer
4y >= 8x - 52 Divide thru by 4:-
y >= 2x - 13
D