Question

Solve each equation using elimination. 2a+3b=12 5a- b=13

Answer 1

$\left \{ {{2a+3b=12} \atop {5a-b=13\ \ | *3}} \right. \\\\ \left \{ {{2a+3b=12} \atop {15a-3b=39}} \right. \\+-----\\ add\ both\ equations\\\\ 17a=51\ \ \ | divide\ by\ 17\\\\ a=3\\\\ b=5a-13\\\\ b=5*3-13=15-13=2\\\\ b=2$