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Daniel [21]
4 years ago
10

Solve each equation using elimination. 2a+3b=12 5a- b=13

Mathematics
1 answer:
natita [175]4 years ago
8 0
\left \{ {{2a+3b=12} \atop {5a-b=13\ \ | *3}} \right. \\\\  \left \{ {{2a+3b=12} \atop {15a-3b=39}} \right. \\+-----\\ add\ both\ equations\\\\
17a=51\ \ \ | divide\ by\ 17\\\\
a=3\\\\
b=5a-13\\\\
b=5*3-13=15-13=2\\\\
b=2
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