Help please! Complete the proof!

Mathematics

1 answer:

Dmitry [639]3 years ago

5 0

Since CM is perpendicular to AB, it follows that ∠1 and ∠2 are 90 degrees. Since they both have 90 degree angles, that must mean they are both right triangles.

And since ∠3 = ∠4 and ∠1 = ∠2, then it follows that ∠A = ∠B. (You can show this by showing that they must add up to 180 degrees.)

So since both right triangles have 3 congruent angles to each, then that makes them similar by AAA (angle angle angle).

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Help 20 points helpppppppp math helps 20 points no linos or imma report you.

bagirrra123 [75]

Answer:

Not a right triangle

Step-by-step explanation:

We can figure out if it is a right triangle or not by using the pythagorean theorem.

a^2 + b^2 = c^2

In this case a and b are 16 and 18

In order for it to be a right triangle, c has to equal 34, in this problem.

16^2 + 18^2 = c^2

= 580^2

= $\sqrt{580}$ = 24.0832

Since 24.0832 does not equal 34, this is not a right triangle

5 0

3 years ago

A ^-4 / a ^-6 please simplify and show your work if possible <:D

kipiarov [429]

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{a^{-4}}{a^{-6}}\implies a^{-4}\cdot a^6\implies a^{-4+6}\implies a^2$