Let the angle of elevation is x and the height of the rocket from the ground is y
tanx = y/15
by differentiating both sides with respect to T
sec²x·dx/dt = (dy/dt)/15
at y = 30 , the hypotenuse of the triangle = 15√5
sec²x=(15√5/15)²=5
5 dx/dt = 11/15
dx/dt = 11/75 rad/sec
Answer:
The answer is 120
Step-by-step explanation:
3 places. 6 options in the first place, 5 options in the second place, and then 4 in the last place. Because one option is used every time you pick one.
6x5x4=120
One is a fraction the other is a whole number
Answer:
19/30
Step-by-step explanation:
1/5 + 2/15 + 3/10
We need the LCD of 5, 15, and 10.
LCD = 30
1/5 + 2/15 + 3/10 =
= 6/30 + 4/30 + 9/30
= 19/30
Answer: 19/30
Answer:
1679616
Step-by-step explanation:
