We know that
if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant
cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13
Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13
the answer Part A) is
cos (x/2)=-6√√13/13
Part B) sin (2x)
sin (2x)=2*sin x* cos x------> 2*[-12/13]*[5/13]----> -120/169
the answer Part B) is
sin(2x)=-120/169
Answer:
yes
Step-by-step explanation:
4/6 of 100 = 66.6666666667
three-dimensional graphs wouldn´t give you the right information but two-dimensional graphs would give you the actual size of the shape.
The slope of any line can be calculated using the following rule:
slope = (y2-y1) / (x2-x1)
The given points are (-14,-10) and (7,5), therefore:
y2 = 5
y1 = -10
x2 = 7
x1 = -14
Substitute with these values to get the value of the slope as follows:
slope = (5--10) / (7--14) = 5/7
