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3 years ago

14

You have a recipe for coconut cookies. The recipe makes 20 cookies. You need 100 cookies for a bake sale. Increase the recipe pr

oportionally to make 100 cookies.

1 answer:

lozanna [386]3 years ago

7 0

Answer:

repeat this 5 times

Your welcome

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A diver ascended 8/9 of a meter in 1/9 of a minute. What was the diver's rate of ascent in meters per minute?

Akimi4 [234]

Answer:

8m/mins

Step-by-step explanation:

The following were obtained from the question:

Distance = 8/9m

Time = 1/9min

Rate = Distance /time

Rate = (8/9) / (1/9) = 8/9 x 9

Rate = 8m/mins

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3 years ago

Solve by both sides variable josh has two leaking pipes in his basement. while waiting for the plumber to come, josh puts a buck

aleksandrvk [35]

First off, you misspelled some words, second WHICH BUCKET does josh's brother take? That's important!

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4 years ago

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

zhannawk [14.2K]

Answer:

$- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$

Step-by-step explanation:

We have to find the quotient of the following division, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$ .

Now, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$

= $- \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]}$ {Since all the terms in the expression are in product form, so we can treat them separately}

{Since we know the property of exponent as $\frac{a^{b} }{a^{c} } = a^{(b - c)}$ }

= $- \frac{3}{4} p^{8} q^{-3}$

= $- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$ (Answer)

{Since we know, $a^{-b} = \frac{1}{a^{b} }$ }

3 0

3 years ago

Read 2 more answers

Under what conditions can a lender repossess a vehicle?

schepotkina [342]

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5 0

3 years ago

I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

5 0

3 years ago