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klemol [59]
3 years ago
7

Explain how you could use the dimensions of a reduced rectangle and one given measurement of an original rectangle to find a mis

sing measure?
Please and thank you
Mathematics
2 answers:
noname [10]3 years ago
6 0
You could use a proportion and cross-multiply. For example, if the reduced rectangle had a length of 3 and a width of 5, and then the one measurement of the original rectangle is length of 7, you could set a proportion like:
3/5 = 7/x

Then, cross multiply to solve for x, and that sound give the missing measure. 
hichkok12 [17]3 years ago
5 0

Using the given measurements of both figures, set up a proportion that has the corresponding parts in the same position. Then solve the proportion using cross products to find the value for the unknown.

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A water skier is pulled behind a boat by a rope. The rope has a tension of 290 N and is at an angle of 33 degrees. What is the x
Yanka [14]
Answer this question by trigonometry.
Draw the rope at an angle of 33 degrees from the x axis.

You will find:
cosx = a/h
cos33 = a/290
a. = 243.21
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3 years ago
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Find the slope of the line graphed below.​ 21 points!
PolarNik [594]
The answer is 3/2
3 units up and 2 units to the left that is the slope
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What is the simplified expression for 6 (2 (y x))? 6 y 12 x 12 y 12 x 12 y 8 x 8 y 8 x
stellarik [79]

The simplified expression for 6(2( y + x)) is 12y + 12x.

Accordin to the given question.

We have an expression

6(2( y + x))

Therefore,

The simplified expression for 6(2( y + x)) is given by

6(2(y + x))

= 6(2y + 2x)          (by distributive law)

= 12y + 12x              (by distributive law)

Hence, the simplified expression for 6(2( y + x)) is 12y + 12x.

Find out more information about simplified expression here:

brainly.com/question/18077352

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5 0
1 year ago
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
GIVING BRAINLIEST
Arte-miy333 [17]

Answer:

i dont know

Step-by-step explanation:

8 0
2 years ago
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