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miv72 [106K]
2 years ago
14

Help with this question

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0
I think the answe might be B
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7 0
3 years ago
Read 2 more answers
Please please please help me. I have no idea what to do
rewona [7]
We have a bunch of rectangles making up the lateral sides of this figure. They have side length 12 and height 13.

So the area of one rectangle is 12 x 13 = 156.
We have 6 of these rectangles, so our lateral area is 6(156) = 936.

The total surface area requires that we include the area of the base. To find the area of a regular polygon we take half of the product of the apothem and perimeter.

A = (1/2)*a*p

The apothem is given to be 10.39,
and the perimeter is fairly easy to calculate:
With the side length being 12, the perimeter is then 6(12) = 72.

So then the area of our base is (1/2)*10.39*72 = 374.04

So then the total surface area is the (base area) + (lateral area),
374.04 + 936 = 1310.04
3 0
3 years ago
Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16.
Sedaia [141]
15, since 16-1=15, and you can use the y-intercepts as points to measure the distance from.
7 0
2 years ago
Order from least to greatest. -1/5,1/7,-0.5,1/8
Ivenika [448]

There ya go, Hope, this helps

5 0
3 years ago
The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?
Paul [167]

Answer:

The standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Let (x_{1},y_{1}) and (x_{2},y_{2}) be the given points (6,2) and (-2,5) respectively.

M=(\frac{6-2}{2},\frac{2+5}{2})

M=(\frac{4}{2},\frac{7}{2})

M=(2,\frac{7}{2})

Therefore the center (h,k) is (2,\frac{7}{2})

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

=\sqrt{(-2-6)^2+(5-2)^2}

=\sqrt{(-8)^2+(3)^2}

=\sqrt{64+9}

=\sqrt{73}

Therefore the radius is \sqrt{73}

i.e., r=\sqrt{73}

Therefore the standard form of the circle is

(x-h)^2+(y-k)^2=r^2

Now substituting the center  and radiuswe get

(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2

(x-2)^2+(y-\frac{7}{2})^2=73

Therefore the standard form of the given circle is

(x-2)^2+(y-\frac{7}{2})^2=73

5 0
3 years ago
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