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Mandarinka [93]

3 years ago

10

What is the degree of 6x5 - 4x2 + 2x3 - 3 + x?

2 answers:

ivanzaharov [21]3 years ago

7 0

(I am assuming that for example, in 6x5 the exponent is 5, so the expression is 6x⁵ - 4x² + 2x³ - 3 + x)
Finding the degree of a polynomial is really simple. All you have to do is find the largest exponent in the polynomial, so in this case, the degree is 5 (Yes, my previous answer is wrong) and not 26. I don't know how you got 26.
Another example: In 3x² - 8x⁷ + 6xy⁴, the degree is 7.

Evgen [1.6K]3 years ago

7 0

Answer:

55555555555555555555

Step-by-step explanation:

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Read 2 more answers

Solve the differential equation. y' + 5xey = 0.

Gwar [14]

Answer:

The solution is $y = - ln(\frac{5}{2}x^{2} + C)$

Step-by-step explanation:

To solve the differential equation, we will find $y$

From the given equation, y' + 5xey = 0.

That is, $y' + 5xe^{y} = 0$

This can be written as

$\frac{dy}{dx} + 5xe^{y} = 0$

Then,

$\frac{dy}{dx} = - 5xe^{y}$

$\frac{dy}{e^{y}} = - 5x dx$

Then, we integrate both sides

$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

$\int {e^{-y}dy }} =\int {- 5x dx}$

Then,

$-e^{-y} = -\frac{5}{2}x^{2} + C$

$e^{-y} = \frac{5}{2}x^{2} + C$

Then,

$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

Hence,

$y = - ln(\frac{5}{2}x^{2} + C)$

8 0

3 years ago

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