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Mandarinka [93]

2 years ago

10

What is the degree of 6x5 - 4x2 + 2x3 - 3 + x?

2 answers:

ivanzaharov [21]2 years ago

7 0

(I am assuming that for example, in 6x5 the exponent is 5, so the expression is 6x⁵ - 4x² + 2x³ - 3 + x)
Finding the degree of a polynomial is really simple. All you have to do is find the largest exponent in the polynomial, so in this case, the degree is 5 (Yes, my previous answer is wrong) and not 26. I don't know how you got 26.
Another example: In 3x² - 8x⁷ + 6xy⁴, the degree is 7.

Evgen [1.6K]2 years ago

7 0

Answer:

55555555555555555555

Step-by-step explanation:

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ZanzabumX [31]

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Step-by-step explanation:

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7 0

2 years ago

Which pair of words is the ODD one out. A. sister-brother, B. wife-husband, C. teacher-student or D. princess-prince

wel

Answer:

C. teacher-student

Step-by-step explanation:

the pattern is girl, boy, girl boy, and teacher and student don't have a gender connection

8 0

3 years ago

Is this a acute angel

Nana76 [90]

Answer:

YES MA'AM

Step-by-step explanation:

3 0

3 years ago

Find the derivative of f(x)=x+1/x-1 using first principal

zepelin [54]

f ' ( x ) = 1 ( x + 1 ) 2

Explanation:

differentiating from first principles

f ' ( x ) = lim h → 0

f ( x + h ) − f ( x ) h

f ' ( x ) = lim h → 0

x + h x + h + 1 − x x + 1 h

the aim now is to eliminate h from the denominator

f ' ( x ) = lim h =0

( x + h ) ( x + 1 )− x ( x + h + 1) h ( x + 1 ) ( x + h + 1 )

f ' ( x ) = lim h → 0

x 2 + h x + x + h − x 2 − h x − x h ( x + 1 ) ( x+h + 1 )

f ' ( x ) = lim h → 0

h 1 h 1 ( x + 1 ) ( x + h +1 )

f ' ( x ) = 1 ( x + 1 ) 2

5 0

3 years ago

What is the area of the rectangle?

den301095 [7]

Answer:

$50\ units^{2}$

Step-by-step explanation:

Plot the figure to better understand the problem

see the attached figure

we know that

If the figure is a rectangle

then

$AB=CD \\AD=BC$

The area of the rectangle is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AD

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\B(0,-5)$

substitute the values

$d=\sqrt{(-5-5)^{2}+(0+5)^{2}}\\d=\sqrt{(-10)^{2}+(5)^{2}}\\dAB=\sqrt{125}\ units$

Step 2

Find the distance AD

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\D(-1,7)$

substitute the values

$d=\sqrt{(7-5)^{2}+(-1+5)^{2}}\\d=\sqrt{(2)^{2}+(4)^{2}}\\dAD=\sqrt{20}\ units$

Step 3

Find the area of the rectangle

$A=AB*AD$

we have

$dAB=\sqrt{125}\ units\\dAD=\sqrt{20}\ units$

substitute

$A=\sqrt{125}*\sqrt{20}\\A=\sqrt{2,500}\\A=50\ units^{2}$

7 0

3 years ago