Answer:
Area 14 = PQRS + UVW; Area 16 = ABCD + EFG
Step-by-step explanation:
PQRS: A = lw = 7 × 2 = 14
ABCD: A = lw = 4 × 4 = 16
UVW: A = ½bh = ½ × 7 × 4 = 14
EFG: A = ½bh = ½ × 8 × 4 = 16
Area 14 = PQRS + UVW
Area 16 = ABCD + EFG
The ones that are divisible are 6, 3, 2, 11, and 4.
<span><span><span>2r - 9 > -6
</span><span>2r - 9 = -6
</span>2r = 3</span><span>
r = 3/2 = 1.5</span></span><span><span>
r > 1.5</span></span>
<span><span /></span><span><span>9x-5 < -41
</span><span>9x-5 = -41
9x = -36
x = -36/9 = -4
x < -4</span></span>
<span><span>3x + 13 > 7
3x + 13 = 7
3x = -6
x = -6/3 = -2
x > -2</span></span>
<span><span>4x + 3 > -17
4x + 3 = -17
4x = -20
x = -20/4 = -5
x > -5</span></span>
<span><span>7x - 4 < 10
7x - 4 = 10
7x = 14
x = 14/7 = 2
x < 2</span></span><span>
</span>
Formula is y = a(x-h)^2 + k
Where h is 1 and k is 1
f (x) = a(x-1)^2 + 1
-3 = a(0-1)^2 + 1
-3 = a(-1)^2 + 1
-3 = a(1) + 1
-3 - 1 = a
-4 = a
a = -4
A must be equal to -4
y = -4(x-1)^2 + 1
0 = -4(x-1)^2 + 1
4(x^2 - 2x + 1) - 1 = 0
4x^2 - 8x + 4 - 1 = 0
4x^2 - 8x + 3 = 0
4x^2 - 8x = -3
Divide fpr 4 each term of the equation....x^2 - 2x = -3/4
We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 =
(-1)^2 = 1 and we add up that to both sides
x^2 - 2x + 1 = -3/4 + 1
x^2 - 2x + 1 = 1/4
(x-1)^2 = 1/4
square root both sides x-1 = (+/-) 1/2
x1 = +1/2 + 1 = 3/2
x2 = -1/2 + 1 = 1/2
x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)
