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Ket [755]
3 years ago
10

The coordinates of (2,-4) rotated 90° is:

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
It should be (4,2) going clockwise, i think it would SAY counterclockwise because usually we go clockwise
Grace [21]3 years ago
6 0
Clockwise: (-4,-2)
Counterclockwise: (4,2)

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Find the equation of the line that passes through the given points
uranmaximum [27]
First you need to figure out the slope:
y2-y1/x2-x1=(1+5)/(-5-7)=-1/2

y+5=-1/2(x-7)
y=-1/2x-3/2
6 0
3 years ago
I need help with these two
Alika [10]

Answer:

19. A

20. A

Step-by-step explanation:

19. tan(53)=15/x

x(tan(53))=15

x=15/(tan53))

x=11.3 feet


20. tan(60)=12/x

x(tan(60))=12

x=12/(tan(60))

x=6.93, or 4sqrt3

4 0
3 years ago
I NEED THE ANSWER IN THE NEXT MINUTE
OverLord2011 [107]

Answer:

508.68

*sorry if this is late

Step-by-step explanation:

Divide 36 by 2 to get radius

Multiply 18 by itself to get 324

Multiply 324 by 3.14 to get the area of a circle

Divide it by 2 to get the area of the semi circle

7 0
3 years ago
Simplify the expression.<br><br><br> Write your answer without negative exponents.
Phoenix [80]

Answer:

-5/ (x^19 * y^12)

Step-by-step explanation:

-15x^-10 * y ^ -3 * x^-9 * y^-9/3 (It's writing it like this.)

15 and 3 have a GCF of 3.

-5x^-10 * y^-3 * x^-9 * y^-9/1

Reduce similar occurrences. *twice in a row*

-5x^(-10 + (-9)) * y^(-3 + (-9))/1

Remove extra signs *twice in a row*

-5x^(-10 - 9) * y^(-3 - 9)/1

Remove extraneous 1.

-5x^(-10 - 9) * y^(-3 - 9)

Add integers.

-5x^-19 * y^-12

Negative powers change multiplication to division.

-5 / (x^19 * y^12) is the final answer.

Even with that, the simplified answer wouldn't have negative exponents because of the negative powers rule.

8 0
2 years ago
The measure of angle A is 15°, and the length of side
dangina [55]

Answer:

Part 1) AB=30.9\ units

Part 2) AC=29.9\ units

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

sin(A)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(15^o)=\frac{8}{AB}

solve for AB

AB=\frac{8}{sin(15^o)}=30.9\ units

Part 2

Find the length side AC

we know that

tan(A)=\frac{BC}{AC} ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

tan(15^o)=\frac{8}{AC}

solve for AC

AC=\frac{8}{tan(15^o)}=29.9\ units

8 0
3 years ago
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