F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
BD = 46
Explanation:
BC = CD and AC is used for both triangles so AD MUST = AB.
If AB = 23, then AD = 23.
BD = AB + AB
BD = 23 + 23
BD = 46
Answer: whats the question here?
(9y+y) + (6+3)
The answer is 10y+9
Answer:
x = 21
Step-by-step explanation:
11x – 32 = 31 + 8x
11x = 63 + 8x
3x = 63
x = 21
