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GREYUIT [131]
3 years ago
8

Between x = 2 and x = 3, which function has a greater average rate of change than y = 1 3 -x ?

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0
Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]
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This line has a Y-intercept of <br><br>A. 0<br><br>B. 1<br><br>C.2<br><br>D.3​
insens350 [35]

Answer:

The y-intercept is 3 aka. (0,3)

Step-by-step explanation:

The slope is 1 (since (6-4)/(3-1)=2/2=1)

y=1x+b

4=1+b

3=b

4 0
3 years ago
Read 2 more answers
What are the real zeros of the function g(x) = x3 + 2x2 − x − 2?
Nat2105 [25]
Upon a slight rearrangement this problem gets a lot simpler to see.

x^3-x+2x^2-2=0  now factor 1st and 2nd pair of terms...

x(x^2-1)+2(x^2-1)=0

(x+2)(x^2-1)=0  now the second factor is a "difference of square" of the form:

(a^2-b^2) which always factors to (a+b)(a-b), in this case:

(x+2)(x+1)(x-1)=0

So g(x) has three real zero when x={-2, -1, 1}
4 0
3 years ago
A company has budgeted 5 1/4 hours to complete a project, with 1/3 of the time spent on research. How much time does the company
elena-s [515]

Given that a company budgeted 5 1/4 hours to complete a project, determine how much time they spent on research if they spent 1/3 of the total budget.

First, convert the budget from hours into minutes.

5 1/4 hours = 315 minutes

1 hour = 60 min

1/4 hour = 15 min

60 x 5 = 300

300 + 15 = 315

Then, divide the minutes by 3 or multiply it by 1/3.

315 / 3 = 105

315 x 1/3 = 105

Lastly convert to a mixed number.

1 3/4 hour

Thus, the company plans to spend 1 3/4 hours or 1 hour and 45 minutes on research.

7 0
3 years ago
$10,000 is invested at two different rates. $2,500 is invested at 4%, and the rest is invested at 5%. How much interest is earne
worty [1.4K]
I'm assuming this is a yearly interest.

2500*.04=100
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so that would be $475 earned from interest
3 0
3 years ago
wanting some extra help with factoring while knowing what method it would be like gcf or grouping etc
Ksju [112]

d) You have a <u>difference of squares</u>:

49y² - 9 = (7y)² - 3²

Recall the identity,

a² - b² = (a - b) (a + b)

So,

49y² - 9 = (7y - 3) (7y + 3)

e) Pull out the common factor 3 from each term:

3x² - 3x - 90 = 3 (x² - x - 30)

Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so

3x² - 3x - 90 = 3 (x + 5) (x - 6)

f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so

x² - 13x + 42 = (x - 7) (x - 6)

8 0
2 years ago
Read 2 more answers
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