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castortr0y [4]
3 years ago
11

2 1/2 miles equals how many feet?​

Mathematics
2 answers:
alexdok [17]3 years ago
7 0

well there are 5280 ft in one mile .

Natasha2012 [34]3 years ago
3 0

The conversion from miles to feet is 1 mile equals 5,280 feet.

So, if we multiply 2 and a half (or 2.5) by 5,280, we get 13,200 feet.

I hope I helped you!

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A landscaper mowed 2 1/4 yards in 1 1/2 hours. How much did she mow in 1 hour? How many hours does it take to mow one yard?
ioda

Answer:

1.5 or 1 1/2 of a lawn in one hour. about one hour to mow one yard.

Step-by-step explanation:

6 0
3 years ago
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What is the estimate of 172.6 divided by 39 ?
KengaRu [80]
To the nearest tenth = 4.4 and to the nearest whole number is 4. Whatever estimation it asks you.
5 0
3 years ago
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Simplyfi. (9g^10p^8)^2<br> givin brainlest to first correct
Cloud [144]

Answer:

= 9 {g}^{20}  {p}^{16}

hope this helps

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3 0
4 years ago
what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base
JulsSmile [24]

Answer :

  • 301.44 cm³

⠀

Explanation :

We know,

{ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}

Where,

  • <em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

  • <em>h</em> is the height of the cylinder. Here, height is 6 cm

  • Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \it{ \pmb{ Volume_{(cylinder)}  {= 301.44 \: }}}}}}

⠀

Therefore,

  • The volume of the cylinder is 301.44 cm³ approximately.
6 0
3 years ago
Read 2 more answers
Plz somebody help. ^_^
pickupchik [31]

Answer:

sin θ =  15/17

Step-by-step explanation:

First we have to know how much the hypotenuse measures.

to take out the hypotenuse we will use pitagoras, with the following formula.

h^2 = c1^2 + c2^2

c1 = 8

c2 = 15

h^2 = 8^2 + 15^2

h^2 = 64 + 225

h = √ 289

h = 17

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin θ = o/h

cos θ= a/h

tan θ = o/a

we want to know the sin of θ

sin θ = o/h

sin θ =  15/17

5 0
4 years ago
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