$\dfrac{\left(\dfrac{4}{3}ab^3\right)\left(\dfrac{6}{2}a^4\right)}{a^5}=\dfrac{\left(\dfrac{\not4^2}{\not3_1}\cdot\dfrac{\not6^2}{\not2_1}\right)(aa^4)(b^3)}{a^5}=\dfrac{4a^5b^3}{a^5}=\boxed{4b^3}$

3 0

3 years ago

Find the following probabilities based on the standard normal variable Z. (You may find it useful to reference the z table

hammer [34]

Answer:

Step-by-step explanation:

a. P(Z > 1.12) = 1-N(1.12) = 1-0.8686431=0.1313569

b. P(Z S-2.35) => P(Z <= 2.35) = 0.009386706

(please check interpretation of question b)

c. POSZ s 1.34) => P(0 <= Z <= 1.34) = 0.9098773 - 0.5 = 0.4098773

(please check interpretation of question c)

d. P(-0.8 sz s 2.44) => P(-0.8 <= 2.44) = 0.9926564 - 0.2118554 = 0.780801

(please check interpretation of question d)

7 0

3 years ago