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kherson [118]
3 years ago
13

8. There are 4,800 plastic spoons in a case.

Mathematics
1 answer:
g100num [7]3 years ago
7 0

Answer:

Each box has 800 spoons.

Step-by-step explanation:

4800/6=800

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For what value of b makes this equation true? (Solve for b)<br> b +9 = -2
neonofarm [45]

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▹ Answer

<em>b = -11</em>

▹ Step-by-Step Explanation

b + 9 = -2

     -9   -9

b = -2 - 9

b = -2 + -9

b = -11

Hope this helps!

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Is a measure of 25 inches​ "far away" from a mean of 16 ​inches? As someone with knowledge of​ statistics, you answer​ "it depen
erik [133]

Answer:

a) 25 is 3 standard deviation from the mean

b) Is far away from the mean, only 0,3 % away from the right tail

c) 25 is pretty close to the mean (just a little farther from 1 standard deviation)

Step-by-step explanation:

We have a Normal Distribution with mean 16 in.

Case a) we also have a standard deviation of 3 inches

3* 3 = 9  

16 (the mean) plus 3*σ  equal 25 in. the evaluated value, then the value is 3 standard deviation from the mean

Case b) 25 is in the range of 99,7 % of all value, we can say that value is far away from the mean, considering that is only 0,3 % away from the right tail

Case c) If the standard deviation is 7 then

mean + 1*σ  =  16 + 7 =23

25> 23

25 is pretty close to the mean only something more than 1 standard deviation

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3 years ago
What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

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3 years ago
What is the probability that he picks up a blue pen and recognizes it as blue?
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We have no factors to go by
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