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olasank [31]
3 years ago
12

If a dairyman has 300 pounds of milk testing 3% butterfat, how many pounds of skimmed milk (with no butterfat) must he remove to

have milk testing 3.6% butterfat?
Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

60 pounds of skimmed milk to be removed

Step-by-step explanation:

Given that 300 pounds of milk is testing 3 % of milk

It means;

3% of fats = 300 pounds of milk

or

1% of fats = 100 pounds of milk -------------(1)

Now let x% of fat be added to present value of fats so that it becomes 3.6% of fats

i-e

x+3=3.6

this gives  x=0.6% of fats needs to be increased

but from eq (1)    we know  

1% of fats =100 pounds of milk

so, 0.6% of fats = 0.6x100=60 pounds of skimmed milk is to be removed .

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A roundabout of a radius 7 yd laid with a carpet grass. find the area of the roundabout laid with carpet grass
Novay_Z [31]

Area of roundabout = 153.86 yd2

we are given,

radius = 7 yd

Area of circle = π r^{2}

= 3.14 × 7× 7

= 153.86 yd2

<h3>What is the area of circle?</h3>

The area of a circle is the space occupied by the circle in a two-dimensional plane. Alternatively, the space occupied within the boundary/circumference of a circle is called the area of the circle. The formula for the area of a circle is A = πr2, where r is the radius of the circle. The unit of area is the square unit,

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3 0
2 years ago
Srekar needs to increase the size of the prism below by 2 inches on each side. The original prism has a length of 3, a depth of
Leto [7]

Answer:

a b

Step-by-step explanation:

The options as obtained from the internet.

- the new prism will have a length of 5

- the new prism will have a depth of 4

- the new prism will have a height of 2

- the volume will increase by 6 and each of the 3 dimensions is increased by 2.

- srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

The volume of a rectangular prism is (length × depth × height)

Originally, length = 3 inches

Depth = 2 inches

Height = 1 inch

Original volume = 3×2×1 = 6 in³

Then, Sreka adds 2 inches to each of the dimensions,

New length = 3+2 = 5 inches

New depth = 2+2 = 4 inches

New height = 1+2 = 3 inches

New volume = (5×4×3) = 60 in³

Taking each of the statements one at a time

Statement 1

the new prism will have a length of 5

True!

Statement 2

the new prism will have a depth of 4

True!

Statement 3

the new prism will have a height of 2

False! New height = 3 inches

Statement 4

the volume will increase by 6 and each of the 3 dimensions is increased by 2.

This is false. The volume increased to 10 folds of its original volume.

Statement 5

srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

Adding 6 inches to the height,

New height = 1+6 = 7 inches

New volume = 3×2×7 = 42 in³

This statement is false as the new volume from adding 2 inches to each side is 60 in³

Hope this Helps!!!

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