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3 years ago

12. What is the radius of a circle with circumference 5 cm?

Mathematics

2 answers:

zalisa [80]3 years ago

7 0

What the person above said for sure

Veseljchak [2.6K]3 years ago

4 0

Answer:

C=pi(radius)^2

c=pi(5)^2

c=pi(25)

c=78.5398163397...

c is about 78.5

Step-by-step explanation:

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What is the answer to 1n-10=5/6-7-1/3n

navik [9.2K]

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1*n-((5/6)*n)+(1/3)*n-10+7 = 0

n+(-5/6)*n+(1/3)*n-10+7 = 0

1/2*n-3 = 0 // + 3

1/2*n = 3 // : 1/2

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That's just in case you had to show your work lol^^

3 0

3 years ago

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Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

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dalvyx [7]

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12. What is the radius of a circle with circumference 5 cm?​

12. What is the radius of a circle with circumference 5 cm?