Answer:
1. a. b = - 8
b. x = 8
c. x = 11
d. x = 5
2. 12 soccer balls and 8 basketballs can be purchased.
Step by step explanation
a.
Calculate the sum
Collect like terms
Move variable to L.H.S and change it's sign
Similarly, Move constant to R.H.S and change its sign
Collect like terms
Change the signs on both sides of the equation
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b.
Apply cross product property
Multiply the numbers
Move constant to R.H.S and change its sign
Calculate the difference
Divide both sides of the equation by 5
Calculate
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c.
Apply cross product property
Multiply the numbers
Swap the sides of the equation
Move constant to R.H.S and change its sign
Calculate
Change the signs on both sides of the equation
Divide both sides of the equation by 8
Calculate
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D.
Distribute 5 through the parentheses
Collect like terms
Swap both sides of the equation
Move constant to R.H.S and change its sign
Calculate the sum
Divide both sides of the equation by 11
Calculate
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2.
Solution,
No.of students in soccer = x
No.of students in basketball = y
Total no.of students = 20
i.e x + y = 20 → equation ( i )
Cost of soccer ball = $ 7
Cost of basketball = $ 10
Total budget = $ 164
i.e 7x + 10 y = 165 → equation ( ii )
In equation ( i ),
x + y = 20
Move 'y' to R.H.S and change its sign
x = 20 - y
Put the value of x in equation ( i )
Now, put the value of y in equation ( i ) ,
x + y = 20
Hence, 12 soccer balls and 8 basketballs can be purchased.
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