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4 years ago

I have been cleaning cars for 35 minutes. I have completed 6 cars how many minutes did it take me to clean 1 car

Mathematics

1 answer:

postnew [5]4 years ago

4 0

5.8 minutes
35 minutes divides by 6 cars = 5.83

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Help me with this! Solve for x

olganol [36]

Answer:

x=6

Step-by-step explanation:

Line ZW and YX are parallel, which means they have the same measurements.

Therefore:

3x+2=20

subtract two from both sides

3x=18

divide by 3

3x/3=18/3

x=6

hope this helps =D

5 0

3 years ago

Sara has a stack of 8 plates, each plate is 0.5 inches tall and she is trying to wrap them as a gift.

AlekseyPX

Answer:

The plates will not fit into the box.

Step-by-step explanation:

Each plate is 0.5 inches tall; therefore, the stack of 8 plates will have a height of $0.5in*8 = 4inches$ .

Also, the diameter of the largest plate is 10 inches or has a radius of 5 inches, which matches the radius of the cylindrical box; therefore, we know that the stack of plates can fit into the base area of the cylindrical box.

What we want to figure out now is the height of the cylindrical box to see if it is greater than or equal to 4 inches—the height of the stack of plates.

The volume of a cylinder is $\pi R^2h$ , and since for our cylindrical box the volume is 150 cubic inches; therefore,

$\pi R^2h = 150in^3$

putting in $R = 5in$ and solving for height $h$ we get

$h = \dfrac{150in^3}{\pi (5)^2}$

$h = 1.91\: inches$ ,

which is not greater than 4 inches, which means the plates will not fit into the box since the height of the stack is greater than the height of the box.

5 0

4 years ago

Which expression is equivalent to (2x-5)-(3x-8) A.-x-13 B.-x+3 C.2x-16 D.5x-3

kramer

Answer is B.-x+3

(2x-5)-(3x-8)
= 2x-5-3x+8
=-x + 3

4 0

3 years ago

A certain rectangular prism has a height of 6 m, a length of 5 m, and a width of 4 m. Give the dimensions of a second rectangula

trasher [3.6K]

Answer:

$height = length = width = \sqrt \frac{74}{3}$