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OLga [1]
3 years ago
15

Given the following equation, at what point will the graph intersect? f(x) =5x+1 g(x)= -2x+15

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer: (2,11)

Step-by-step explanation:

To find the point where the functions will intersect, we want to find the place that they are equal to each other. We do this by setting the equations equal to each other.

5x+1=-2x+15                       [add both sides by 2x]

7x+1=15                               [subtract both sides by 1]

7x=14                                  [divide both sides by 7]

x=2

Now, we know that the functions intersect at x=2. To find the point, we would plug x back into both equations to ensure that the points are the same.

f(2)=5(2)+1                         [multiply]

f(2)=10+1                            [add]

f(2)=11

The point on f(x) is (2,11).

g(2)=-2(2)+15                    [multiply]

g(2)=-4+15                         [add]

g(2)=11

The point on g(x) is (2,11).

Since the point at x=2 is the same for f(x) and g(x), we know that the graph intersects at (2,11).

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Answer:

13

Step-by-step explanation:

I am amusing you are looking for the hypotenuse since this is middle school.

If you have the legs and are looking for the hypotenuse you use the Pythagorean Theorem a^{2} + b^{2} = c^{2}

The legs are a and b, and the hypotenuse is c

The work would look like this

13^{2} + 5^{2} = c^{2} \\169+25= c^{2} \\194= c^{2} \\\sqrt{194} = \sqrt{c^{2} } \\13.9283883... = c

extra notes

  • I rounded to 13
  • If you didn;t know you cancles exponents with roots

so the c^{2} is cancled by aka \sqrt{c}

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