All categories

3 years ago

Plz help me understand how to solve this (the question is at the box on the bottom ty)

Mathematics

1 answer:

abruzzese [7]3 years ago

3 0

You would get the annual salaries by dividing each total salary by the number of years it took to earn it. For example, to get the physician's annual salary, you would divide 5,610,000 by 30 to get an answer of $187,000.

You might be interested in

Simplify: 5a + 1r + 2a + 4r

Marina CMI [18]

Answer:

7a+5r

Step-by-step explanation:

5a + 1r + 2a + 4r

add like terms

7a+5r

hope that helps

4 0

2 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

2 years ago

Pls answer BOTH of these

Juli2301 [7.4K]

Answer:

#1 i think is 2x7 i dont know #2 sry

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Số hạng đầu và số hạng thứ 2 của một cấp số nhân lần lượt là x+2 và x^2 -4 số hạng thứ 3 của cấp số nhân này là

GenaCL600 [577]

Answer:

x³-2x²-4x+8

Step-by-step explanation:

a1=x+2

a2=x²-4⇒q=a2/a1=x-2

⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8

3 0

2 years ago

Write an equation for the nth term of the geometric sequence 6000,3000,1500,750 <br> PLEASE HELP!!!

Wewaii [24]

Answer: $6000\cdot (1/2)^{n-1}$

Each term is half of the previous one, so the common ratio is 1/2. Then to get from the first term to the nth term, you have to take n - 1 steps, multiplying by 1/2 each time and by 6000 to account for the first term.

i hope this helps! :D

8 0

2 years ago