Help plz.......................!
1 answer:
Average rate of change is also known as the slope. If we look at the x values of 2 and 4, the population for the deer is the same number. In rise over run, that would be (8.5-8.5)/(4-2) which is 0/2 or 0. There is no change over that interval. The other question is asking us to find the first x value in that interval where the slope is -300. Year 5 has a deer population of 700, so fitting that into the slope formula we have 
. The first x value for that interval is 5. Your empty boxes will have 0 and 5 as your answers.
You might be interested in
Answer:
Step-by-step explanation:
So the first step is to add like terms since you can simplify the numerator by adding the two values sine they have the same variable and degree.
Add like terms:
Divide by 2x (divide coefficient by 2, subtract coefficient degrees)
Multiply exponents and raise 4 to the power of 5
The reason you multiply exponents is because you can think about it like this:
(4 * x * x * x * x * x * x * x * x) (this has one 4 and 8 x's because x is raised to the power of 8. Now if you do that 5 times which is what the exponent is doing you're going to have 40 x's and 8 4's. So it's essentially
(4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x). If you group like terms you'll get (4 * 4 * 4 * 4 * 4) * (x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x). Which simplifies to 4^5 * x ^ (8 * 5) which further simplifies to the answer 1024x^40