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3 years ago

(3x/2)^4 any answers

Mathematics

2 answers:

avanturin [10]3 years ago

8 0

Simplify the expression by distributing the exponent of 4 to both 3, x and 2:

3 raised to the 4th power is 81, x raised to the fourth power is x^4 and 2 raised to the 4th power is 16.

So your answer is 81x^4/16.

:)))

Anika [276]3 years ago

6 0

$\bf \left( \cfrac{3x}{2} \right)^4\implies \left( \cfrac{(3x)^4}{2^4} \right)\implies \left( \cfrac{3^4x^4}{2^4} \right)\implies \cfrac{81x^4}{16}$

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is this correct?: data can be arranged in visual displays called _graphs_ to make identifying trends easier. (or would it be bar

andrew-mc [135]

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4 0

3 years ago

How to find degrees in triangle using trig?

nordsb [41]

Remember SOHCAHTOA

Sine- opposite/hypotenuse
Cosine- adjacent/hypotenuse
Tangent- opposite/adjacent

Look at the angle (x) you are trying to figure out and pick which one of these it is.

In your calculator, do the equation first to get a decimal

Then press whichever one you chose on the calculator, so if you got like 0.2 by doing opposite/adjacent for tangent, you would type in 0.2 and then the TAN button

hope this makes sense!!

8 0

3 years ago

GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!

Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

------------------

The first equation is of the line.
The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

$x + 2y = 6$

$2y = 6 - x$

$y = -0.5x + 2$

Thus it is a decreasing line, which removes options J.

We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

------------------

As for the second equation, the normalized equation is:

$3x^2 + 3y^2 = 12$

$3(x^2 + y^2) = 12$

$x^2 + y^2 = 4$

Thus, a circle centered at the origin and with radius 2.
Now, we have to check if the line $x + 2y - 6 = 0$ , with coefficients $a = 1, b = 2, c = -6$ , intersects the circle, of centre $x = 0, y = 0$
First, we find the following distance:

$d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}$

Considering the coefficients of the line and the center of the circle.

$d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1$

This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0

3 years ago

Write the equation of the circle graphed below.

Darina [25.2K]

Answer:

Your equation is $(x - 1)^2 + (y +1)^2 = (\frac{1}{2} )^2$

Step-by-step explanation:

Well, the center origin of the circle is given (h,k) = (1,-1).

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (1,-1) and (x,y) = (0.5,-1) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

(0.5 - (1))^2 + (-1 - (-1))^2 = r^2

(-0.5)^2 + (0)^2 = r^2

1/4= r^2

r^2 = 1/4

r = 1/2

6 0

2 years ago

I need to know how to do this step my step and the answer

MissTica

You can use the calculator or 0^2 is 0 x -3 =0 +7 (0) -4 =-4

5 0

3 years ago