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harkovskaia [24]
3 years ago
9

find a model for simple harmonic motion if the position at t=0 is 0 the amplitude is 5 centimeters and the period is 4 seconds

Mathematics
2 answers:
Alexeev081 [22]3 years ago
7 0

Answer:

y = 5sin(\frac{x}{2})

Step-by-step explanation:

Since harmonic motion is represented by the sine wave equation.

y = a sin (bx)

where a = amplitude

period = \frac{2\pi}{b}

Amplitude of the harmonic motion is given as 5 and period is 4 seconds.

so a = 5

and 4 = \frac{2\pi}{b} ⇒ b = \frac{2\pi}{4}

b = \frac{\pi}{2}

Now we replace the values of a and b in the sine equation

y = 5sin(\frac{x}{2})

Jobisdone [24]3 years ago
6 0
<span>d = 5sin(πt) 
hope this helped</span>
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