Answer: The expected waiting time is 
Step-by-step explanation:
Since we have given that
Average waiting time for slow elevator = 3 min
Average waiting time for fast elevator = 1 min
probability that a person choose the fast elevator = 
Probability that a person choose the slow elevator = 
So, the expected waiting time would be
![E[x]=\sum xp(x)=3\times \dfrac{1}{3}+1\times \dfrac{2}{3}\\\\=1+\dfrac{2}{3}\\\\=\dfrac{3+2}{3}\\\\=\dfrac{5}{3}\\\\=1\dfrac{2}{3}\ min](https://tex.z-dn.net/?f=E%5Bx%5D%3D%5Csum%20xp%28x%29%3D3%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%2B1%5Ctimes%20%5Cdfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%3D1%2B%5Cdfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%3D%5Cdfrac%7B3%2B2%7D%7B3%7D%5C%5C%5C%5C%3D%5Cdfrac%7B5%7D%7B3%7D%5C%5C%5C%5C%3D1%5Cdfrac%7B2%7D%7B3%7D%5C%20min)
Hence, the expected waiting time is
Answer:
Water is not wet, it makes things wet.
<em>y-intercept</em><em> </em><em>is</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>graph</em><em> </em><em>crosses</em><em> </em><em>through</em><em> </em><em>the</em><em> </em><em>y-axis</em>
Formula for surface area of a sphere of radius r is A = 4pi*r^2.
The same formula, for the case where the radius is 2.45 times greater, comes out to A = 4pi*[2.45r]^2.
Just find the ratio of
4pi*r^2 to 4pi*[2.45r]^2. It is 1/6.
Angles 1 and 3 are the answers
