What is the graph for y ≤ -3

Mathematics

1 answer:

kirill115 [55]3 years ago

3 0

Answer:

Step-by-step explanation:

To graph an inequality, find the value on the number line. Find -3. Since this is a less than or equal to, plot a closed circle. Then shade and point an arrow in the direction which other numbers satisfy the inequality. For example, -4 is less than or equal to -3 so on. Point the arrow to the left. This is answer choice A.

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6x + 5y = 147 8x + 4y = 156

satela [25.4K]

Answer:

[12, 15]

Step-by-step explanation:

{6x + 5y = 147

{8x + 4y = 156

-¾[8x + 4y = 156]

{6x + 5y = 147

{-6x - 3y = -117 ← New Equation

________________

2y = 30

___ ___

2 2

y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x

So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all x-terms. It does not matter which variable you choose to eliminate, as long as you know what you are doing.

I am joyous to assist you anytime.

3 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

.........i think it’s 56 i’m not sure though

Hunter-Best [27]

it is 56

because you need to break the figure into two parts

5 x 4 = 20

4 x 9 = 36

5 0

3 years ago

Write the first 4 terms for f (1) = 3, f (n) = [f(n-1)]